Y=5x^2-80x+320

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Solution for Y=5x^2-80x+320 equation: 



=5Y^2-80Y+320

We move all terms to the left:

-(5Y^2-80Y+320)=0

We get rid of parentheses

-5Y^2+80Y-320=0

a = -5; b = 80; c = -320;
Δ = b2-4ac
Δ = 802-4·(-5)·(-320)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{-80}{-10}=+8$

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